How do you find the value for $cos^(-1) [(cos(135')]$ ?

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Answer 1 · 2015-06-25T16:08:31

$cos^(-1)[cos(135')] = 135'$

$cos^(-1)(x)$ or $arccos(x)$ is the angle, $theta$ for which $cos(theta) = x$ .

If $x = cos(135')$ then $theta = 135'$

(It is unusual to have specified the angle in minutes; if it is relevant, note: $135' = 2^o15'$ )

How do you find the value for cos^(-1) [(cos(135')]cos^(-1) [(cos(135')]?