How do you find the value for ${sin}^{- 1} (- \frac{7}{3})$ $sin^-1 (-7/3)$ ?

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Answer 1 · 2018-06-18T04:15:24

$since (- \frac{7}{3}) < - 1 given sine term cannot exist$ $color(crimson)("Since " (-7/3) < -1 " given sine term cannot exist"$

$Let θ = {sin}^{- 1} (- \frac{7}{3})$ $"Let " theta = sin ^-1 (-7/3)$

$sin θ = - (\frac{7}{3})$ $sin theta = -(7/3)$

$sin θ can have a value between - 1 & + 1 only$ $sin theta " can have a value between "-1 " & " +1 " only"$

$since (- \frac{7}{3}) < - 1 given sine term cannot exist$ $color(crimson)("Since " (-7/3) < -1 " given sine term cannot exist"$

How do you find the value for sin−1(−73)sin^-1 (-7/3) ?