How do you find the value for $tan (arccos (\frac{2}{3}))$ $tan(arccos(2/3))$ ?

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Answer 1 · 2015-06-13T18:03:18

Find value of $tan (arccos (\frac{2}{3}))$ $tan (arccos (2/3))$

On the trig unit circle,

$cos x = \frac{2}{3} - \to x = \pm 48.19$ $cos x = 2/3 --> x = +- 48.19$

$tan (\pm 48.19) = \pm 1.12$ $tan (+- 48.19) = +- 1.12$

How do you find the value for tan(arccos(23)) tan(arccos(2/3))?