How do you find the value for $tan [{tan}^{- 1} (7.4)]$ $tan[tan^-1(7.4)]$ ?

Question

How do you find the value for $tan [{tan}^{- 1} (7.4)]$ $tan[tan^-1(7.4)]$ ?

1 Answer

Impact of this question

2757 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-01T22:44:53

By definition $tan ({tan}^{- 1} (7.4)) = 7.4$ $tan(tan^-1(7.4)) = 7.4$

More explicitly:

Let $α = {tan}^{- 1} (7.4)$ $alpha = tan^-1(7.4)$

Then by definition $α$ $alpha$ is the unique angle such that $tan α = 7.4$ $tan alpha = 7.4$ and $- \frac{π}{2} < α < \frac{π}{2}$ $-pi/2 < alpha < pi/2$ .

Science

Math

Humanities

... and beyond

How do you find the value for $tan [{tan}^{- 1} (7.4)]$ $tan[tan^-1(7.4)]$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the value for tan[tan−1(7.4)]tan[tan^-1(7.4)]?

1 Answer

Related questions

Impact of this question

How do you find the value for $tan [{tan}^{- 1} (7.4)]$ $tan[tan^-1(7.4)]$ ?