How do you find the value of $arctan (tan (\frac{5 π}{6}))$ $arctan(tan((5pi)/6))$ ?

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How do you find the value of $arctan (tan (\frac{5 π}{6}))$ $arctan(tan((5pi)/6))$ ?

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Answer 1 · 2015-07-02T20:52:50

It would be $\frac{5 π}{6}$ $(5pi)/6$ as $arctan$ $arctan$ and $tan$ $tan$ camcel out.

Explanation:

$tan$ $Tan$ answers the question: what ratio is there between the opposite and the adjoining side when the angle is $\frac{5 π}{6}$ $(5pi)/6$

$arctan$ $Arctan$ answers the opposite question: what angle belongs to a certain ratio of opposite and adjoining sides.

$tan$ $tan$ and $arctan$ $arctan$ are opposing operators, comparable to square and square root, or multiplication and division. They cancel out each other.

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How do you find the value of $arctan (tan (\frac{5 π}{6}))$ $arctan(tan((5pi)/6))$ ?

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How do you find the value of $arctan (tan (\frac{5 π}{6}))$ $arctan(tan((5pi)/6))$ ?