How do you find the value of ${csc}^{- 1} (- 1)$ $csc^-1(-1)$ ?

Question

14749 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-29T22:19:51

$θ = - 90^{\circ} (270^{\circ})$ $theta=-90^@(270^@)$

${csc}^{- 1} (- 1)$ $csc^-1(-1)$

$csc θ = - 1$ $csctheta=-1$

$\frac{1}{sin θ} = - 1$ $1/sintheta=-1$

$sin θ = \frac{1}{- 1}$ $sintheta=1/-1$

$sin θ = - 1$ $sintheta=-1$

$θ = {sin}^{- 1} (- 1)$ $theta=sin^-1(-1)$

$θ = - 90^{\circ} (270^{\circ})$ $theta=-90^@(270^@)$

How do you find the value of csc^-1(-1)csc−1(−1)csc^-1(-1)?