How do you find the value of #csc ((pi)/2)#?

2 Answers
Alan P.
May 25, 2015

#csc(theta) = 1/sin(theta)#

#sin(pi/2) = 1# (this is a basic relation)

#rarr csc(pi/2) = 1#

Gió
May 25, 2015

Well, #csc(x)=1/sin(x)# so basically, I would find #sin(pi/2)# and use it to get:
#csc(pi/2)=1/(sin(pi/2))=1/1=1#

Graphically:
![http://www.mathnstuff.com/math/spoken/here/2class/300/fx/library/http://trigfx.htm](https://useruploads.socratic.org/NdpwL5sOQ5GUVr94otrU_graph30.jpg)

Remember also that:
![http://www.mathnstuff.com/math/spoken/here/1words/c/c43.htm](useruploads.socratic.org)

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