Question

How do you find the value of k so that the remainder is zero given `(2x^3-x^2+x+k)div(x-1)`?

Answer 1

The value of `k=-2`

Explanation:

Let `f(x)=2x^3-x^2+x+k`

If `(x-1)` is a factor

By the remainder theorem

We have `f(1)=2-1+1+k=0`

Therefore, `k=-2`