How do you find the value of k so that the remainder is zero given $(2x^3-x^2+x+k)div(x-1)$ ?

Question

3979 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-23T17:40:36

The value of $k=-2$

Let $f(x)=2x^3-x^2+x+k$

If $(x-1)$ is a factor

By the remainder theorem

We have $f(1)=2-1+1+k=0$

Therefore, $k=-2$

How do you find the value of k so that the remainder is zero given (2x^3-x^2+x+k)div(x-1)(2x^3-x^2+x+k)div(x-1)?