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How do you find the value of k so that the slope of the line through the points (4 , 2) and (k , 6) is equal to -2?

1 Answer

Feb 4, 2015

The answer is: $k = 2$ $k=2$ .

Given two point, $A (x_{a}, y_{a})$ $A(x_a,y_a)$ and $B (x_{b}, y_{b})$ $B(x_b,y_b)$ the slope of the line that passes from them is:

$m = \frac{y_{b} - y_{a}}{x_{b} - x_{a}}$ $m=(y_b-y_a)/(x_b-x_a)$ .

So:

$- 2 = \frac{6 - 2}{k - 4} \Rightarrow - 2 (k - 4) = 4 \Rightarrow$ $-2=(6-2)/(k-4)rArr-2(k-4)=4rArr$

$- 2 k + 8 = 4 \Rightarrow - 2 k = - 4 \Rightarrow k = 2$ $-2k+8=4rArr-2k=-4rArrk=2$ .

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