Question

How do you find the value of `sec^-1[(2sqrt 3)/3]`?

Answer 1

Find arcsec ((2sqrt3)/3)

Ans: `pi/6 and (5pi)/6`

Explanation:

sec x = 1/(cos x). First, find cos x
`cos x = 3/(2sqrt3) = sqrt3/2` --> arc `x = +-pi/6`
Ans: `x = pi/6` and `x = (5pi)/6`