How do you find the value of $sin (\frac{2 π}{3})$ $sin ((2pi)/3)$ ?

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Answer 1 · 2016-06-27T06:59:08

$sin (\frac{2 π}{3}) = \frac{\sqrt{3}}{2}$ $sin((2pi)/3)=sqrt3/2$

As $sin 2 A = 2 sin A cos A$ $sin2A=2sinAcosA$

$sin (\frac{2 π}{3}) = 2 sin (\frac{π}{3}) cos (\frac{π}{3})$ $sin((2pi)/3)=2sin(pi/3)cos(pi/3)$

= $2 \times \frac{\sqrt{3}}{2} \times \frac{1}{2}$ $2xxsqrt3/2xx1/2$

= $1cancel(2)xxsqrt3/2xx1/(1cancel(2))$

= $sqrt3/2$

How do you find the value of sin ((2pi)/3)sin(2π3)sin ((2pi)/3)?