How do you find the value of #tan(-(5pi)/12)#?
1 Answer
Aug 15, 2017
Explanation:
Find
In this case:
cos pi/12 is positive, so, take the positive value.
sin^2 ([i/12) = 1 - cos^2 (pi/12) = 1 - (2 + sqrt3)/4 = (2 - sqrt3)/4
sin (pi/12) = +- sqrt(2 - sqrt3)/2
sin (pi/12) is positive, so, take the positive value.