Question

How do you find the value of `tan(arcsin(1/2))`?

Answer 1

`-sqrt3/3 and sqrt3/3`

Explanation:

Trig table of special arcs, and trig unit circle -->
sin x = 1/2 --> arc `x = pi/6`, and arc `x = (5pi)/6`

a. `x = pi/6 --> tan x = sqrt3/3`
b. `x = (5pi)/6 --> tan x = -sqrt3/3`