How do you find the value of $tan ({tan}^{- 1} (\frac{1}{2}))$ $tan(tan^-1 (1/2))$ ?

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Answer 1 · 2016-07-20T09:38:43

$\frac{1}{2}$ $1/2$

$tan ({tan}^{- 1} (\frac{1}{2}))$ $tan(tan^(-1)(1/2))$ is the mathematical form of the expression

"tangent of the angle whose tangent is $\frac{1}{2}$ $1/2$ ".

There could be no second opinion on the value $= \frac{1}{2}$ $=1/2$ "..

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