How do you find the value of the determinant #|(12,-26), (-15,32)|#? Precalculus Matrix Algebra Determinant of a Square Matrix 1 Answer Narad T. Dec 6, 2016 The answer is #=-6# Explanation: The calculation of a #2#x#2# determinant is # | (a,b), (c,d) | # #=a*d-b*c# So, # | (12,-26), (-15,32) | =12*32-(-26)*(-15)# #=12*32-26*15=384-390=-6# Answer link Related questions What is the determinant of an inverse matrix? What is the determinant of a matrix used for? What is the determinant of a matrix to a power? What is meant by the determinant of a matrix? How do I find the determinant of a #2xx2# matrix? How do I find the determinant of a #3xx3# matrix? How do I find the determinant of of a #4xx4# matrix? How do I find the determinant of of a #5xx5# matrix? Does every matrix have a determinant? What is the cofactor expansion method to finding the determinant? See all questions in Determinant of a Square Matrix Impact of this question 1952 views around the world You can reuse this answer Creative Commons License