How do you find the value of the monomial $2.1 m^{2} n p^{3}$ $2.1m^2 np^3$ for: m= -0.61, n= 32, p=4.7?

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Answer 1 · 2018-05-09T16:48:53

The answer $\approx 2596.1066$ $~~color(red)(2596.1066)$

First, write out the expression:

$2.1 m^{2} n p^{3}$ $2.1m^2np^3$

And substitute your values:

$2.1 {(- 0.61)}^{2} (32) {(4.7)}^{3}$ $2.1(-0.61)^2(32)(4.7)^3$

Solve for exponents first:

$2.1 (0.3721) (32) (103.823)$ $2.1(0.3721)(32)(103.823)$

And multiply across:

$0.78141 (32) (103.823)$ $0.78141(32)(103.823)$
$25.00512 (103.823)$ $25.00512(103.823)$
$\approx 2596.1066$ $~~color(red)(2596.1066)$

How do you find the value of the monomial 2.1m2np32.1m^2 np^3 for: m= -0.61, n= 32, p=4.7?