How do you find the vertex, focus and sketch #x^2+8y=0#?

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Answer 1 · 2018-07-12T23:09:07

Vertex #(0, 0)# & focus #(0, -2)#

Given equation:

#x^2+8y=0#

#x^2=-8y#

Above equation shows a downward parabola with

Vertex: #(0, 0)#

Focus: #(0, -2)#

The parabola has axis of symmetry #x=0# i.e. y-axis. Specify the vertex & focus on y-axis & make a free hand curve of parabola with arms downwards