How do you find the vertex, focus and sketch $x^2+8y=0$ ?

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Answer 1 · 2018-07-12T23:09:07

Vertex $(0, 0)$ & focus $(0, -2)$

Given equation:

$x^2+8y=0$

$x^2=-8y$

Above equation shows a downward parabola with

Vertex: $(0, 0)$

Focus: $(0, -2)$

The parabola has axis of symmetry $x=0$ i.e. y-axis. Specify the vertex & focus on y-axis & make a free hand curve of parabola with arms downwards

How do you find the vertex, focus and sketch x^2+8y=0x^2+8y=0?