How do you find the vertex form of a quadratic equation? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Massimiliano Feb 20, 2015 Since the equation is: #y=x^2+bx+c# the vertex is #V(-b/(2a),-Delta/(4a))#, or, found the #x_v=-b/(2a)# you can substitue it in the equation of the parabola at the place of #x#, finding the #y_v#. Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? How do you write #y=3x^2-18x+5# in vertex form? See all questions in Vertex Form of a Quadratic Equation Impact of this question 25620 views around the world You can reuse this answer Creative Commons License