How do you find the vertical, horizontal and slant asymptotes of: $\frac{x}{x^{2} + x - 6}$ $x/(x^2+x-6)$ ?

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Answer 1 · 2016-12-22T18:42:29

Vertical asymptotes x=-3 and x=2

Horizontal asymptote at y=0

No slant asymptote

Rewrite f(x) after factorising the denominator as follows

$f (x) = \frac{x}{(x + 3) (x - 2)}$ $f(x)= x/((x+3)(x-2))$

f(x) has vertical asymptotes at x= -3 and x=2. It has an horizontal asymptotes at y=0 There are no slant asymptotes

How do you find the vertical, horizontal and slant asymptotes of: x/(x^2+x-6)xx2+x−6x/(x^2+x-6)?