How do you find the vertical, horizontal or slant asymptotes for $f(x)= -1/(x+1)^2$ ?

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Answer 1 · 2016-03-02T15:07:30

$x=-1$ Vertical Asymptote
$y=0$ Horizontal Asymptote
No Slant Asymptote

y approaches zero when x approaches infinity therefore $y=0$ is a horizontal asymptote.

x approaches -1 when y approaches infinity therefore $x=-1$ is a vertical asymptote

$(x+1)^2=-1/y" " "$ when y is so large, the right sides of the equation is almost zero and

$x+1=0$

God bless...I hope the explanation is useful..

How do you find the vertical, horizontal or slant asymptotes for f(x)= -1/(x+1)^2f(x)= -1/(x+1)^2?