How do you find the vertical, horizontal or slant asymptotes for $f (x) = \frac{1}{x^{2}}$ $f(x)= 1/x^2$ ?

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Answer 1 · 2018-08-08T12:40:16

Vertical asymptote is at $x = 0$ $x=0$ ,horizontal asymptote is at $y = 0$ $y=0$ (x axis).

$f (x) or y = \frac{1}{x^{2}}$ $f(x) or y=1/x^2$

Vertical asymptote occur when denominator is zero.

$x^2=0 :. x=0; lim(x->0^-) ,y -> (+oo)$

$lim (x->0^+), y -> (+oo)$

Vertical asymptote is at $x=0$

Horizontal asymptote: $lim (x->+-oo) ; y =0$

Horizontal asymptote is at $y=0$ (x axis)

If the numerator's degree is greater (by a margin of 1), then we

have a slant asymptote , so there is no slant asymptote.

graph{1/x^2 [-10, 10, -5, 5]}[Ans]

How do you find the vertical, horizontal or slant asymptotes for f(x)= 1/x^2f(x)=1x2f(x)= 1/x^2?