Question

How do you find the vertical, horizontal or slant asymptotes for `f(x) = ( 3x^2 + 2x - 1 )/( x + 1)`?

Answer 1

f(x) has no asymptotes.

Explanation:

The first step is to factorise and simplify f(x).

`f(x)=((3x-1)cancel((x+1)))/cancel((x+1))=3x-1`

Now f(x)= 3x - 1 is the equation of a line and has no asymptotes.
graph{3x-1 [-10, 10, -5, 5]}