Question

How do you find the vertical, horizontal or slant asymptotes for `f(x)= (x+3)/( x^2+4x+3)`?

Answer 1

Vertical Asymptote: `x=-1`
Horizontal Asymptote: `y=0`

Explanation:

From the given `y=(x+3)/(x^2+4x+3)=(x+3)/((x+3)(x+1))=1/(x+1)`

graph{y=(x+3)/(x^2+4x+3)[-20,20,-10,10]}

God bless....I hope the explanation is useful.