How do you find the vertical, horizontal or slant asymptotes for $f(x)=(x-4)^2/(x^2-4)$ ?

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Answer 1 · 2016-06-04T03:54:53

Vertical asymptotes x= 2, x= -2

Horizontal asymptote y=1

Vertical asymptotes are given by Eq $x^2-4=0$ which gives x=2, x=-2

For slant/horizontal asymptotes write f(x) = $1 +(20-8x)/(x^2-4)$

Asymptote given by y=1 is a horizontal asymptote. There is no slant asymptote

How do you find the vertical, horizontal or slant asymptotes for f(x)=(x-4)^2/(x^2-4) f(x)=(x-4)^2/(x^2-4) ?