How do you find the vertical, horizontal or slant asymptotes for $(x^2 - 5x + 6)/( x - 3)$ ?

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Answer 1 · 2017-01-25T12:39:17

$y = 1$ , at x = 3 and $y = x-2, x ne 3 to y = x-2$ , for $x in R$ .

No asymptotes.

As $y = ((x-2)(x-3))/(x-3)$ , we can redefine y as follows.

$y = 1$ , at x = 3 and

$y = x-2, x ne 3$

How do you find the vertical, horizontal or slant asymptotes for (x^2 - 5x + 6)/( x - 3) (x^2 - 5x + 6)/( x - 3) ?