How do you find the volume bounded by #x^2y^2+16y^2=6# and the x & y axes, the line x=4 revolved about the x-axis?
1 Answer
Nov 16, 2016
= 3.7011 cubic units, nearly.
Explanation:
The graph of
In
the parallel x = 4 at
The volume is
= 3.7011 cubic units, nearly.-
graph{x^2y^2+16y^2-6=0 [-10, 10, -5, 5]}