How do you find the volume bounded by #x-8y=0# & the lines #x+2y# revolved about the y-axis?
1 Answer
Volume of revolution =
Explanation:
The ihtersection of the two lines happen to be,
^3Considering y axis to represent the height of the cone,
Area of cross section is given by
where,
r is the x coordinate.
For x-8y=0, from y=0 to y=a/10,
x=8y
A=pi(x)^2
A=pi(8y)^2
Volume1 =
For x=2y=1 from y=a/10 to y=a/2
A=pi(x)^2
Volume2=
Volume2=
Volume of revolution = Volume1+Volume2
Volume of revolution =