How do you find the volume bounded by y=ln(x) and the lines y=0, x=2 revolved about the y-axis?

2 Answers
Aug 7, 2017

For the solution by cylindrical shells, see below.

Explanation:

Here is a picture of the region and a representative slice taken parallel to the axis of rotation.

enter image source here

The slice is taken at some value of x and has thickness dx. So our functions will need to be functions of x

Revolving about the y axis will result in a cylindrical shell.

The volume of this representative shell is

2pirh " thickness"

The radius is shown as a dashed black line in the picture and has length r = x

The height of the shell will be the great y value minus the lesser y value. Since the lesser y value is 0, we have h = lnx
As already mentioned, the thickness is dx

The representative volume is
2pixlnxdx

x varies from 1 to 2, so the solid has volume

V = int_1^2 2pixlnx dx = 2 pi int_1^2 xlnx dx

Use integration by parts to get

= 2pi(2ln2-3/4)

(Rewrite the answer to taste.)

Aug 7, 2017

For the solution by washers see below.

Explanation:

Here is a picture of the region and a representative slice taken perpendicular to the axis of rotation.

enter image source here

The slice is taken at some value of y and has thickness dy. So our functions will need to be functions of y

The curve y = lnx can also be represented by x = e^y

Revolving about the y axis will result in a washer.

The volume of this representative washer is

piR^2 *" thickness" - pir^2 " thickness" = pi(R^2-r^2) *" thickness"

Where R is the greater radius -- shown as a dashed line. And r is the lesser radius -- shown as a dotted line.

In this case R = "the "x" value on the right" = 2
and R = "the "x" value on the left" = e^y

The representative volume is
pi(2^2-(e^y)^2) dy = pi(4-e^(2y))dy

x varies from 1 to 2,

so y varies from 0 to ln2

And the volume is

V = int_0^(ln2) pi(4-e^(2y))dy = piint_0^(ln2) (4-e^(2y))dy

Use integration to get

= pi[(4ln2-1/2e^(2ln2))-(-1/2e^0)] = pi(4ln2-3/2)

(Rewrite the answer to taste.)