How do you find the x and y intercept and slope of $Y=1/2x+6$ ?

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Answer 1 · 2015-07-10T23:56:39

The $y$ -intercept is at ( $0,6$ ), and the $x$ -intercept is at ( $-12,0$ ).

The "slope-intercept" form of a straight line equation is

$y = mx + b$ ,

where $m$ is the slope and $b$ is the $y$ -intercept.

Your equation is

$Y = 1/2x +6$

If we compare the two equations, we see that $b = 6$ .

So the $y$ -intercept is at ( $0,6$ ).

To get the $x$ -intercept, we set $Y = 0$ and solve for $x$ .

$Y = 1/2x + 6$

$0 = 1/2x + 6$

$0 = x + 12$

$x = -12$

The $x$ -intercept is at ( $-12,0$ ).

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How do you find the x and y intercept and slope of Y=1/2x+6Y=1/2x+6?