How do you find the x and y intercept and slope of $y = - \frac{6}{5} x + 6$ $y= - 6/5x + 6$ ?

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Answer 1 · 2015-07-10T22:38:56

The slope is $- \frac{6}{5}$ $-6/5$ , the $y$ $y$ -intercept is at ( $0, 6$ $0,6$ ), and the $x$ $x$ -intercept is at ( $5, 0$ $5,0$ ).

The "slope-intercept" form of a straight line equation is

$y = m x + b$ $y = mx + b$ ,

where $m$ $m$ is the slope and $b$ $b$ is the $y$ $y$ -intercept.

Your equation is

$y = - \frac{6}{5} x + 6$ $y = -6/5x + 6$

If we compare the two equations, we see that

$m = - \frac{6}{5}$ $m = -6/5$ and $b = 6$ $b = 6$ .

So the slope is $- \frac{6}{5}$ $-6/5$ and the $y$ $y$ -intercept is at ( $0, 6$ $0,6$ ).

To get the $x$ $x$ -intercept, we set $y = 0$ $y = 0$ and solve for $x$ $x$ ,

$y = - \frac{6}{5} x + 6$ $y = -6/5x + 6$

$0 = - \frac{6}{5} x + 6$ $0 = -6/5x + 6$

$0 = - 6 x + 30$ $0 = -6x + 30$

$6 x = 30$ $6x = 30$

$x = \frac{30}{6} = 5$ $x = 30/6 = 5$

The $x$ $x$ -intercept is at ( $5, 0$ $5,0$ ).

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