How do you find the x and y intercept for $2 x + 6 y = - 12$ $2x+6y=-12$ ?

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Answer 1 · 2018-04-01T05:07:24

x- intercept $(- 6, 0)$ $(-6,0)$
y-intercept $(0, - 2)$ $(0,-2)$

Given -

$2 x + 6 y = - 12$ $2x+6y=-12$

To find the x-intercept put $y = 0$ $y=0$

$2 x + 6 (0) = - 12$ $2x+6(0)=-12$

$2 x = - 12$ $2x=-12$

$x = \frac{- 12}{2} = - 6$ $x=(-12)/2=-6$

x- intercept $(- 6, 0)$ $(-6,0)$

To find the y-intercept put $x = 0$ $x=0$

$2 (0) + 6 y = - 12$ $2(0)+6y=-12$

$6 y = - 12$ $6y=-12$

$y = \frac{- 12}{6} = - 2$ $y=(-12)/6=-2$

y-intercept $(0, - 2)$ $(0,-2)$

How do you find the x and y intercept for 2x+6y=−122x+6y=-12?