How do you find the x and y-intercept given $y=2/3x+12$ ?

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Answer 1 · 2015-07-11T12:56:45

To find the intercept with the $x$ axis, let $y = 0$ and solve to get $x=-18$

To find the intercept with the $y$ axis, let $x=0$ and see that $y=12$

When $y=0$ we have:

$2/3x+12 = 0$

Subtract $12$ from both sides to get:

$2/3x=-12$

Multiply both sides by $3/2$ to get:

$x = -12*3/2 = -36/2 = -18$

So the intercept with the $x$ axis is at $(-18, 0)$

When $x=0$ we have:

$y = 2/3*0+12 = 0+12 = 12$

So the intercept with the $y$ axis is at $(0, 12)$

How do you find the x and y-intercept given y=2/3x+12y=2/3x+12?