How do you find the x and y-intercept given #y=2/3x+12#?

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Answer 1 · 2015-07-11T12:56:45

To find the intercept with the #x# axis, let #y = 0# and solve to get #x=-18#

To find the intercept with the #y# axis, let #x=0# and see that #y=12#

When #y=0# we have:

#2/3x+12 = 0#

Subtract #12# from both sides to get:

#2/3x=-12#

Multiply both sides by #3/2# to get:

#x = -12*3/2 = -36/2 = -18#

So the intercept with the #x# axis is at #(-18, 0)#

When #x=0# we have:

#y = 2/3*0+12 = 0+12 = 12#

So the intercept with the #y# axis is at #(0, 12)#