How do you find the x and y intercept of $- 2 x + 5 y = 20$ $-2x+5y=20$ ?

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Answer 1 · 2017-03-30T22:37:52

See the entire solution process below:

Y-Intercept)

To find the y-intercept, set $x$ $x$ equal to $0$ $0$ and solve for $y$ $y$ :

$- 2 x + 5 y = 20$ $-2x + 5y = 20$ becomes:

$(- 2 \cdot 0) + 5 y = 20$ $(-2 * 0) + 5y = 20$

$0 + 5 y = 20$ $0 + 5y = 20$

$5 y = 20$ $5y = 20$

$\frac{5 y}{5} = \frac{20}{5}$ $(5y)/color(red)(5) = 20/color(red)(5)$

$(color(red)(cancel(color(black)(5)))y)/cancel(color(red)(5)) = 4$

$y = 4$

The y-intercept is $4$ or $(0, 4)$

X-Intercept)

To find the x-intercept, set $y$ equal to $0$ and solve for $x$ :

$-2x + 5y = 20$ becomes:

$-2x + (5 * 0) = 20$

$-2x + 0 = 20$

$-2x = 20$

$(-2x)/color(red)(-2) = 20/color(red)(-2)$

$(color(red)(cancel(color(black)(-2)))x)/cancel(color(red)(-2)) = -10$

$x = -10$

The x-intercept is $-10$ or $(-10, 0)$

How do you find the x and y intercept of -2x+5y=20−2x+5y=20-2x+5y=20?