How do you find the x and y intercept of $3 = 7 x + - 5 y$ $3 = 7x + -5y$ ?

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Answer 1 · 2017-04-19T12:28:42

See the entire solution process below:

To find the $x$ $x$ and $y$ $y$ intercept you substitute $0$ $0$ for one of the variables and solve for the other variable.

x-intercept:

Substitute $0$ $0$ for $y$ $y$ and solve for $x$ $x$

$3 = 7 x + (- 5 \cdot 0)$ $3 = 7x + (-5 * 0)$

$3 = 7 x + 0$ $3 = 7x + 0$

$3 = 7 x$ $3 = 7x$

$\frac{3}{7} = \frac{7 x}{7}$ $3/color(red)(7) = (7x)/color(red)(7)$

$3/7 = (color(red)(cancel(color(black)(7)))x)/cancel(color(red)(7))$

$3/7 = x$

The x-intercept is: $3/7$ or $(3/7, 0)$

y-intercept:

Substitute $0$ for $x$ and solve for $y$

$3 = (7 * 0) + -5y$

$3 = 0 - 5y$

$3 = -5y$

$3/color(red)(-5) = (-5y)/color(red)(-5)$

$3/-5 = (color(red)(cancel(color(black)(-5)))y)/cancel(color(red)(-5))$

$-3/5 = y$

The y-intercept is: $-3/5$ or $(0, -3/5)$

How do you find the x and y intercept of 3 = 7x + -5y 3=7x+−5y3 = 7x + -5y ?