How do you find the x and y intercept of $3 x + 0.5 y = 6$ $3x+0.5y=6$ ?

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Answer 1 · 2016-11-07T00:42:08

The $y$ $y$ intercept is 12 and the $x$ $x$ intercept is 2.

To find the $y$ $y$ intercept solve for $x = 0$ $x = 0$ :
$3 \cdot 0 + 0.5 y = 6$ $3*0 + 0.5y = 6$

$0.5 y = 6$ $0.5y = 6$

$\frac{0.5 y}{0.5} = \frac{6}{0.5}$ $(0.5y)/0.5 = 6/0.5$

$y = 12$ $y = 12$

To find the $x$ $x$ intercept solve for $y = 0$ $y = 0$ :

$3 x + 0.5 \cdot 0 = 6$ $3x + 0.5*0 = 6$

$3 x = 6$ $3x = 6$

$\frac{3 x}{3} = \frac{6}{3}$ $(3x)/3 = 6/3$

$x = 2$ $x = 2$

How do you find the x and y intercept of 3x+0.5y=63x+0.5y=6?