How do you find the x and y intercept of $- 3 x + 9 y = - 18$ $-3x+9y=-18$ ?

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Answer 1 · 2017-05-17T14:11:08

The $x$ $x$ -intercept is $(6, 0)$ $(6, 0)$
The $y$ $y$ -intercept is $(0, - 2)$ $(0, -2)$

The $x$ $x$ -intercept occurs when $y$ $y$ equals zero, and the $y$ $y$ -intercept is when $x$ $x$ equals zero.

Knowing that, let's solve for our $x$ $x$ -intercept by setting $y = 0$ $y=0$ .

$- 3 \times x + 9 \times 0 = - 18$ $-3xx x+9xx0=-18$

$- 3 \times x = - 18$ $-3xx x=-18$

divide by $- 3$ $-3$

$x = 6$ $x=6$

The $x$ $x$ -intercept is $(6, 0)$ $(6, 0)$

Now let's solve for the $y$ $y$ -intercept

$- 3 \times 0 + 9 \times y = - 18$ $-3 xx 0+9 xx y=-18$

$9 \times y = - 18$ $9 xx y=-18$

divide by $9$ $9$ on both sides

$x = - 2$ $x=-2$

The $y$ $y$ -intercept is $(0, - 2)$ $(0, -2)$

Just to check our work, let's graph the equation and see if our $x$ $x$ and $y$ $y$ intercepts match:

graph{-18=-3x+9y}

They match! Good job!

How do you find the x and y intercept of −3x+9y=−18-3x+9y=-18?