How do you find the x and y intercept of #4x + y = 5 #?

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Answer 1 · 2016-06-29T07:10:04

#x#-intercept is #5/4# and #y#-intercept is #5#.

For finding #y#-intercept put #x=0#, which gives #y=5#

and for finding #x#-intercept put #y=0#, which gives #x=5/4#

Hence #y#-intercept is #5# and #x#-intercept is #5/4#.

Alternatively if #y#-intercept is #a# and #x#-intercept is #b#, the equation of line is given by #x/a+y/b=1#.

For converting #4x+y=5# into this form let us divide each side by #5#, which gives

#(4x)/5+y/5=1# or

#x/(5/4)+y/5=1# and hence

#x#-intercept is #5/4# and #y#-intercept is #5#.