How do you find the x and y intercept of $4y=3x+12$ ?

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Answer 1 · 2016-12-17T22:10:52

The x-intercept is: $x = -4$ or $(-4, 0$ ).

The y-intercept is: $y = 3$ or (0, 3)

To find the x-intercept you set $y$ equal to $0$ and solve for $x$ :

$4*0 = 3x + 12$

$0 = 3x + 12$

$0 - 12 = 3x + 12 - 12$

$-12 = 3x + 0$

$-12 = 3x$

$(-12)/3 = (3x)/3$

$-4 = x$ or $x = -4$ or $(-4, 0$ ).

To find the x-intercept you set $x$ equal to $0$ and solve for $y$ :

$4y = 3*0 + 12$

$4y = 0 + 12$

$4y = 12$

$(4y)/4 = 12/4$

$y = 3$ or (0, 3)

How do you find the x and y intercept of 4y=3x+124y=3x+12?