How do you find the x and y intercept of $5x - 7y = 1$ ?

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Answer 1 · 2017-06-20T03:33:50

$x$ -intercept: $(1/5, 0); " "y$ -intercept: $(0, -1/7)$

Given: $5x - 7y = 1$

To find the $x$ -intercept, set $y = 0$ and solve for $x$ :

$5x - 7(0) = 1$

$5x = 1$

$(5x)/5 = 1/5$
$x$ -intercept: $(1/5, 0)$

To find the $y$ -intercept, set $x = 0$ and solve for $y$ :

$5(0) - 7y = 1$

$-7y = 1$

$(-7y)/-7 = 1/(-7)$

$y$ -intercept: $(0, -1/7)$

How do you find the x and y intercept of 5x - 7y = 15x - 7y = 1?