To find the x-intercept substitute #color(red)(0)# for #color(red)(y)# and solve for #x#:
#5x - color(red)(y) = 35# becomes:
#5x - color(red)(0) = 35#
#5x = 35#
#(5x)/color(red)(5) = 35/color(red)(5)#
#(color(red)(cancel(color(black)(5)))x)/cancel(color(red)(5)) = 7#
#x = 7#
To find the y-intercept substitute #color(red)(0)# for #color(red)(x)# and solve for #y#:
#5color(red)(x) - y = 35# becomes:
#(5 xx color(red)(0)) - y = 35#
#0 - y = 35#
#-y = 35#
#color(red)(-1) xx - y = color(red)(-1) xx 35#
#y = -35#
The x-intercept is #7# or (7, 0)
The y-intercept is #-35# or (0, -35)