How do you find the x and y intercept of $6x + 4y = 12$ ?

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Answer 1 · 2017-02-27T13:24:33

To find the x-intercept set $y$ equal to $0$ and solve for $x$ :

$6x + 4y = 12$ becomes:

$6x + (4 * 0) = 12$

$6x + 0 = 12$

$6x = 12$

$(6x)/color(red)(6) = 12/color(red)(6)$

$(color(red)(cancel(color(black)(6)))x)/cancel(color(red)(6)) = 2$

$x = 2$ therefore the x-intercept is $2$ or $(2, 0)$

To find the y-intercept set $x$ equal to $0$ and solve for $y$ :

$6x + 4y = 12$ becomes:

$(6 xx 0) + 4y = 12$

$0 + 4y = 12$

$4y = 12$

$(4y)/color(red)(4) = 12/color(red)(4)$

$(color(red)(cancel(color(black)(4)))y)/cancel(color(red)(4)) = 3$

$y = 3$ therefore the y-intercept is $3$ or $(0, 3)$

How do you find the x and y intercept of 6x + 4y = 126x + 4y = 12?