How do you find the x and y intercept of $6x + 8y = - 2$ ?

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Answer 1 · 2016-07-28T19:58:45

$x$ -intecept is $x=-1/3$
$y$ -intecept is $y=-1/4$

$6x+8y=-2$
$x$ -intecept is when $y=0$
So putting $y=0$ in the above equation we get
$6x+8(0)=-2$
or
$6x+0=-2$
or
$6x=-2$
or
$x=-2/6$
or
$x=-1/3$

$y$ -intecept is when $x=0$
So putting $x=0$ in the above equation $6x+8y=-2$
we get
$6(0)+8y=-2$
or
$0+8y=-2$
or
$8y=-2$
or
$y=-2/8$
or
$y=-1/4$

How do you find the x and y intercept of 6x + 8y = - 26x + 8y = - 2?