How do you find the x and y intercept of #8y = 3x - 9#?

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Answer 1 · 2017-06-09T04:23:55

See a solution process below:

To find the #x#-intercept, substitute #0# for #y# and solve for #x#:

#8y = 3x - 9# becomes:

#8 * 0 = 3x - 9#

#0 = 3x - 9#

#0 + color(red)(9) = 3x - 9 + color(red)(9)#

#9 = 3x - 0#

#9 = 3x#

#9/color(red)(3) = (3x)/color(red)(3)#

#3 = (color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3))#

#3 = x#

#x = 3#

The #x#-intercept is #3# or #(3, 0)#

To find the #y#-intercept, substitute #0# for #x# and solve for #y#:

#8y = 3x - 9# becomes:

#8y = (3 * 0) - 9#

#8y = 0 - 9#

#8y = -9#

#(8y)/color(red)(8) = -9/color(red)(8)#

#(color(red)(cancel(color(black)(8)))y)/cancel(color(red)(8)) = -9/8#

#y = -9/8#

The #y#-intercept is #-9/8# or #(0, -9/8)#