How do you find the x and y intercept of $8 y = 3 x - 9$ $8y = 3x - 9$ ?

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Answer 1 · 2017-06-09T04:23:55

See a solution process below:

To find the $x$ $x$ -intercept, substitute $0$ $0$ for $y$ $y$ and solve for $x$ $x$ :

$8 y = 3 x - 9$ $8y = 3x - 9$ becomes:

$8 \cdot 0 = 3 x - 9$ $8 * 0 = 3x - 9$

$0 = 3 x - 9$ $0 = 3x - 9$

$0 + 9 = 3 x - 9 + 9$ $0 + color(red)(9) = 3x - 9 + color(red)(9)$

$9 = 3 x - 0$ $9 = 3x - 0$

$9 = 3 x$ $9 = 3x$

$\frac{9}{3} = \frac{3 x}{3}$ $9/color(red)(3) = (3x)/color(red)(3)$

$3 = (color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3))$

$3 = x$

$x = 3$

The $x$ -intercept is $3$ or $(3, 0)$

To find the $y$ -intercept, substitute $0$ for $x$ and solve for $y$ :

$8y = 3x - 9$ becomes:

$8y = (3 * 0) - 9$

$8y = 0 - 9$

$8y = -9$

$(8y)/color(red)(8) = -9/color(red)(8)$

$(color(red)(cancel(color(black)(8)))y)/cancel(color(red)(8)) = -9/8$

$y = -9/8$

The $y$ -intercept is $-9/8$ or $(0, -9/8)$

How do you find the x and y intercept of 8y = 3x - 98y=3x−98y = 3x - 9?