How do you find the x and y intercept of $y - \frac{3}{5} x - 12$ $y-3/5x-12$ ?

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Answer 1 · 2017-05-28T21:05:44

Assumption: The expression should be an equation and of the form
$y = \frac{3}{5} x - 12$ $y=3/5x-12$

y-intercept $\to (x, y) = (0, - 12)$ $->(x,y)=(0,-12)$
x-intercept $\to (x, y) = (20, 0)$ $->(x,y)=(20,0)$

y-intercept is the same as the constant $\to y = - 12$ $->y=-12$

That is because the y-intercept is at $x = 0$ $x=0$
$y = \frac{3}{5} (0) - 12 = 12$ $y=3/5(0)-12" "=" "12$

y-intercept $\to (x, y) = (0, - 12)$ $->(x,y)=(0,-12)$

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x-intercept is at $y = 0$ $y=0$

$\Rightarrow y = 0 = \frac{3}{5} x - 12$ $=>y=0=3/5x-12$

Add 12 to both sides

$12 = \frac{3}{5} x$ $12=3/5x$

Multiply both sides by 5/3

$\frac{5}{3} \times 12 = \frac{3}{5} \times \frac{5}{3} \times x$ $5/3xx 12=3/5xx5/3xx x$

$5 \times \frac{12}{3} = 1 \times 1 \times x$ $5xx12/3=1xx1xx x$

$20 = x$ $20=x$

x-intercept $\to (x, y) = (20, 0)$ $->(x,y)=(20,0)$

How do you find the x and y intercept of y−35x−12y-3/5x-12?