How do you find the x and y intercepts for 2x - 2y + 5 = 02x−2y+5=0?

2 Answers
Pretish
Jun 12, 2018

Intercepts such that: (-\frac{5}{2},0)(−52,0) and (0,\frac{5}{2})(0,52)

Explanation:

The y intercept will occur when x=0x=0, therefore by subbing in x=0x=0, we isolate y, to form the equation:

-2y+5=0−2y+5=0 which we solve to find y=\frac{5}{2}y=52

The x intercept occurs when y=0y=0 therefore do the same procedure to get:

2x+5=02x+5=0 which we solve to find x=-\frac{5}{2}x=−52

Jim G.
Jun 12, 2018

"x-intercept "=-5/2,"y-intercept "=5/2x-intercept =−52,y-intercept =52

Explanation:

"to find the intercepts, that is where the graph crosses"to find the intercepts, that is where the graph crosses
"the x and y axes"the x and y axes

• " let x = 0, in the equation for y-intercept"∙ let x = 0, in the equation for y-intercept

• " let y = 0, in the equation for x-intercept"∙ let y = 0, in the equation for x-intercept

x=0rArr-2y=-5rArry=5/2larrcolor(red)"y-intercept"x=0⇒−2y=−5⇒y=52←y-intercept

y=0rArr2x=-5rArrx=-5/2larrcolor(red)"x-intercept"y=0⇒2x=−5⇒x=−52←x-intercept

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