Question

How do you find the x and y intercepts for `2x - y = 0`?

Answer 1

x intercept is at x=0 and y intercept is at y-0

Explanation:

This is a straight line graph that look like this:

You find the y intercept by making x=0 in the equation. That is because the graph crosses the y-axis at x=0

You find the x intercept by making y=0 in the equation. That is because the graph crosses the x-axis at y=0

Given:`" "color(brown)( 2x-y=0)`

`color(red)("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~")`
`color(green)("Changing the equation format into:"" " y="something")`

Add`color(blue)(" "y" ")` to both sides giving

`color(brown)(2x-ycolor(blue)(+y)=0color(blue)(+y))`

`color(green)(2x=y)`

`color(red)("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~")`

`color(blue)("To find the x intercept (crosses the x-axis)")`

Set `y=0`

so `y=2x` becomes

`0=2x`

Divide both sides by 2 giving

`0/2= 2/2xx x`

But `0/2=0" and "2/2=1`

`0=1 xx x`

`0=x`

`color(blue)("So the x intercept is at "x=0)`
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
`color(green)("To find the y intercept (crosses the y-axis)")`

Set `x=0` giving

so `y=2x` becomes

`y=2xx 0`

But `2xx0=0`

So `y=0`

`color(green)("So the y intercept is at "y=0)`