How do you find the x and y intercepts for $3 x + 2 y = 10$ $3x + 2y = 10$ ?

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How do you find the x and y intercepts for $3 x + 2 y = 10$ $3x + 2y = 10$ ?

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Answer 1 · 2018-03-27T00:20:49

The x-intercept is at $(\frac{10}{3}, 0)$ $(10/3, 0)$ , and the y-intercept is at $(0, 5)$ $(0,5)$

Explanation:

The x-intercept is where $y = 0$ $y=0$ , and the y-intercept is where $x = 0$ $x=0$ .
X-intercept
$3 x + 2 (0) = 10$ $3x+2(0)=10$
$3 x = 10$ $3x=10$
$x = \frac{10}{3}$ $x=10/3$
x-intercept = $(\frac{10}{3}, 0)$ $(10/3, 0)$
Y-intercept
$3 (0) + 2 y = 10$ $3(0)+2y=10$
$2 y = 10$ $2y=10$
$y = 5$ $y=5$
y-intercept = $(0, 5)$ $(0,5)$

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How do you find the x and y intercepts for $3 x + 2 y = 10$ $3x + 2y = 10$ ?

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