Question

How do you find the x and y intercepts for `-4x-7y+7=0`?

Answer 1

I tried this:

Explanation:

You need to set `x=0` and `y=0` in your expression.

Let us find the `x` intercept; we need to, basically, stay on the `x` axis so that `y` has to be zero (otherwise we are not on the `x` axis).
So, we get:

`y=0`
into your expression:
`-4x-7*color(red)(0)+7=0`
`-4x=-7`
`x=7/4`
So the `x-`axis intercept will be:
`(7/4,0)`

Now for the `y` intercept we need `x` to be zero and we get:
`x=0`
into your expression:
`-4*color(red)(0)-7y+7=0`
`-7y=-7`
`y=7/7=1`
So the `y-`axis intercept will be:
`(0,1)`

Let us check and "see" our intercepts graphically:
graph{-(4/7)x+1 [-10, 10, -5, 5]}

Answer 2

`"x-intercept "=7/4," y-intercept "=1`

Explanation:

`"to find the intercepts that is where the graph crosses"`
`"the x an d y axes"`

`• " let x = 0, in the equation for y-intercept"`

`• " let y = 0, in the equation for x-intercept"`

`-4x-7y+7=0`

`rArr-4x-7y=-7`

`x=0rArr0-7y=-7rArry=1larrcolor(red)"y-intercept"`

`y=0rArr-4x+0=-7rArrx=7/4larrcolor(red)"x-intercept"`
graph{(y+4/7x-1)((x-7/4)^2+(y-0)^2-0.04)((x-0)^2+(y-1)^2-0.04)=0 [-10, 10, -5, 5]}