How do you find the x and y intercepts for $4 y - x = 3$ $4y - x= 3$ ?

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How do you find the x and y intercepts for $4 y - x = 3$ $4y - x= 3$ ?

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Answer 1 · 2015-12-30T10:08:04

$x$ $x$ intercept is $- 3$ $-3$ and $y$ $y$ intercept is $\frac{3}{4}$ $3/4$

Explanation:

For $y = 0$ $y=0$ ,
$\times 4 \times 0 - x = 3$ $color(white)xx4xxcolor(red)0-x=3$
$\Rightarrow - 1 \times - x = - 1 \times 3$ $=>color(red)(-1xx)-x=color(red)(-1xx)3$
$\Rightarrow x = - 3$ $=>x=-3$

For $x = 0$ $x=0$ ,
$\times 4 y = 3$ $color(white)xx4y=3$
$\Rightarrow \frac{1}{4} \times 4 y = \frac{1}{4} \times 3$ $=>color(red)(1/4xx)4y=color(red)(1/4xx)3$
$\Rightarrow y = \frac{3}{4}$ $=>y=3/4$

Thus $x$ $x$ intercept is $- 3$ $-3$ and $y$ $y$ intercept is $\frac{3}{4}$ $3/4$

graph{(1/4)x+3/4 [-10, 10, -5, 5]}

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How do you find the x and y intercepts for $4 y - x = 3$ $4y - x= 3$ ?

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