How do you find the x and y intercepts for $5 x - y + 2 = 0$ $5x-y+2=0$ ?

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How do you find the x and y intercepts for $5 x - y + 2 = 0$ $5x-y+2=0$ ?

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Answer 1 · 2015-11-30T14:19:18

$(0, 2)$ $(0,2)$ and $(- \frac{2}{5}, 0)$ $(-2/5,0)$

Explanation:

$5 x - y + 2 = 0$ $5x-y+2=0$
for $x = 0$ $x=0$ ,
$- y + 2 = 0$ $-y+2=0$
$\Rightarrow y = 2$ $=>y=2$
One of the intercepts is $(0, 2)$ $(0,2)$
for $y = 0$ $y=0$ ,
$5 x + 2 = 0$ $5x+2=0$
$\Rightarrow x = - \frac{2}{5}$ $=>x=-2/5$
The other intercept is $(- \frac{2}{5}, 0)$ $(-2/5,0)$

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How do you find the x and y intercepts for $5 x - y + 2 = 0$ $5x-y+2=0$ ?

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Explanation:

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How do you find the x and y intercepts for $5 x - y + 2 = 0$ $5x-y+2=0$ ?